Jump to content

1884 United States presidential election in Arkansas

From Wikipedia, the free encyclopedia

1884 United States presidential election in Arkansas

← 1880 November 4, 1884 1888 →
 
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 7 0
Popular vote 72,734 51,198
Percentage 57.83% 40.70%

County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Arkansas took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. Arkansas voters chose seven electors to the Electoral College, which selected the president and vice president.

Arkansas voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 17.12%.

Results

[edit]
1884 United States presidential election in Arkansas[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 72,734 57.83% 7 100.00%
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 51,198 40.70% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 1,847 1.47% 0 0.00%
Total 125,779 100.00% 7 100.00%

See also

[edit]

References

[edit]
  1. ^ "1884 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved November 25, 2020.