Prof Bill Buchanan OBE FRSE’s Post

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Professor of Applied Cryptography at Edinburgh Napier University

Bob creates an RSA cipher for a secret message (msg), and sends it to Eve. Bob will decrypt a message for Eve, but not a cipher that he has previously sent. Eve then applies a Chosen Cipher Attack (CCA) on the cipher (using a scalar value), and sends Bob a new cipher. Bob then decrypts it and sends back the decrypted value. Eve makes a quick calculation and can compute the original message. Determine the message for the following. Bob gives cipher for a message of 142840161502703849750073589382026804570883389350146505265129956637401128645654963819090393504021482991624452255433247931550149502314608827960284242591998867988534209443349834399075860450476766953685274975841434870549784413007458681620300220460913454433543818168031389690498032579443546903900446251885893078076 Eve sends a new of cipher: 26945485888977835131560075835828459221886588345659230234537483503561787017229811182439865491409097165354138664962466468765723880398067682494910698500054527944431476361382544679998621899858947543730241637074900609849352140362303197377462233745475057778933309532692476484168262457600125850869002272221678135786 and asks for it to be decrypted. Bob decrypts and gets a value of 256044255078594. Can you find the car manufacturer in the plaintext? Method: https://lnkd.in/eK6A7G95

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