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1 answer
80 views

Mass in de Broglie Formula

Regarding de Broglie formula $$\lambda= h/mv$$ here m is relative mass or rest mass?
SHINU_MADE's user avatar
0 votes
2 answers
161 views

Rigorous derivation of DeBroglie wavelength

I've scoured the internet as much as I can, and I've yet to find a rigorous derivation of the DeBroglie wavelength. They all go something like this: $$E=\gamma mc^2, \ \gamma \approx 1 \ \therefore\ E=...
JBatswani's user avatar
  • 187
1 vote
3 answers
541 views

The Uncertainty in momentum and the de Broglie wavelength

I'd like to pose a straightforward question by providing a brief example to determine whether my current approach is correct or incorrect. Imagine I have an electron confined within a box measuring $1\...
Anky Physics's user avatar
0 votes
3 answers
191 views

What's (intuitively) the $k$ in the de Broglie formula?

Background: I'm currently doing self-study of quantum physics by following university level quantum physics lectures on YouTube (e.g. the YouTube MIT 8.04 Quantum Physics I, Spring 2013 or Stanford ...
Terminality's user avatar
1 vote
2 answers
47 views

If the particle moves with group wave, what $\lambda$ in De Broglie equation should we use?

according to De Broglie equation \begin{gather} p=\frac{h}{\lambda} \end{gather} and knowing also that a particle moves with the group velocity not the phase velocity, indicates that has a range of $\...
amin's user avatar
  • 597
-1 votes
1 answer
49 views

Can you make photons without momentum?

What would it take to make photons without momentum? How would they behave?
Euphorbium's user avatar
0 votes
1 answer
636 views

Can you explain me the definition of wave number as defined in theoretical physics? [duplicate]

Wavenumber, as used in spectroscopy and most chemistry fields, is defined as the number of wavelengths per unit distance. The corresponding formula is $$k=\frac{1}{\lambda}.$$ However, in theoretical ...
Nilabja Kanti Sarkar's user avatar
1 vote
2 answers
264 views

What defines an 'object' with regards to particle-wave duality?

If any object, such as a ball, can exhibit wave behavior, I am confused about how such an object is defined. Does a ball itself have a wavelength? Does every single atom that composes it have a ...
dwib's user avatar
  • 121
4 votes
2 answers
1k views

What is exactly mean by wavelength in De Broglie equation?

I'm wondering what exactly is meant by the wavelength in De Broglie formula $p=\frac{h}{\lambda}$, where $p$ is the momentum of a particle and $\lambda$ is the wavelength. I know that a wave function ...
Ahmed Samir's user avatar
4 votes
2 answers
571 views

Why is de Broglie wavelength related to momentum not energy?

From relativity we have $E^2 = (cp)^2 + (mc^2)^2$ which for a photon ($m = 0$) becomes $E = cp$. From quantum mechanics we have for a photon $E = h\nu = hc/\lambda$. Thus together $$ E = \frac{hc}{\...
Physor's user avatar
  • 870
-3 votes
2 answers
136 views

Does the 1/2 coefficient in kinetic energy stem from Newton, the De Broglie wavelength and length contraction? [closed]

This is my thinking. Everything has a De Broglie wavelength. From this the energy of an object can be calculated. Now due to Special Relativity anything with a velocity experiences length contraction. ...
Tivity's user avatar
  • 287
1 vote
0 answers
223 views

How does wavelength affects uncertainty in momentum & position?

The objective is to locate a microscopic particle, in the presence of light of known wavelength and adjustable accordingly. Brief on the setup. Let there be a box containing the particles to be ...
gobbledy-gook's user avatar
0 votes
1 answer
127 views

de Broglie wavelength for particles with mass [duplicate]

is $p=\frac{h}{\lambda}$ only true for massless particles? because generally $E=\sqrt{p^2c^2+m^2c^4}$, then if we equate it to $h\nu$ we get $$p=\sqrt{\frac{h^2}{\lambda^2}-m^2c^2}\neq\frac{h}{\lambda}...
Darkenin's user avatar
  • 1,038
0 votes
1 answer
199 views

Where to use $E=h \nu$ and $p=h/\lambda$? [closed]

Where to use $E=h \nu$ and $p=h/\lambda$? Because both the methods give different answers. Can somebody explain why is it so?
Nirmal Moray's user avatar
0 votes
2 answers
512 views

What does momentum of Photons mean? [duplicate]

I have already checked out Can a force stop a Photon since Photons have momentum and What does momentum mean when talking about massless particles?, but that didn't answer my query. I already know ...
Koustubh Jain's user avatar

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