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Jul 7 at 2:54 answer added Taladris timeline score: 3
Jul 6 at 19:14 answer added user121330 timeline score: 0
Jul 6 at 6:04 history edited DannyNiu
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Jul 5 at 23:05 comment added Henry If $s$ is distance and $t$ is time, you would interpret $v=\frac{ds}{dt}$ as instantaneous velocity with dimension $[\text{Distance}]\cdot [\text{Time}]^{-1}$ and $a=\frac{dv}{dt}=\frac{d^2s}{dt^2}$ as acceleration $[\text{Distance}]\cdot [\text{Time}]^{-2}$. You can do something similar with integrals.
Jul 5 at 17:28 comment added David Z FWIW it's not true that all three factors are supposed to be from the set of real numbers. They can be quantities with units. (Or potentially even vectors or some such thing that has the right properties to be an integration variable.)
Jul 5 at 15:13 history became hot network question
Jul 5 at 8:53 history edited DannyNiu CC BY-SA 4.0
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Jul 5 at 8:42 history edited Prem CC BY-SA 4.0
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Jul 5 at 8:37 answer added Prem timeline score: -1
Jul 5 at 7:40 history edited DannyNiu CC BY-SA 4.0
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Jul 5 at 7:36 vote accept DannyNiu
Jul 5 at 7:34 answer added Abezhiko timeline score: 22
Jul 5 at 7:11 history asked DannyNiu CC BY-SA 4.0