Timeline for Can the differential be unitless while the variable have an unit in integration?
Current License: CC BY-SA 4.0
13 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jul 7 at 2:54 | answer | added | Taladris | timeline score: 3 | |
Jul 6 at 19:14 | answer | added | user121330 | timeline score: 0 | |
Jul 6 at 6:04 | history | edited | DannyNiu |
edited tags
|
|
Jul 5 at 23:05 | comment | added | Henry | If $s$ is distance and $t$ is time, you would interpret $v=\frac{ds}{dt}$ as instantaneous velocity with dimension $[\text{Distance}]\cdot [\text{Time}]^{-1}$ and $a=\frac{dv}{dt}=\frac{d^2s}{dt^2}$ as acceleration $[\text{Distance}]\cdot [\text{Time}]^{-2}$. You can do something similar with integrals. | |
Jul 5 at 17:28 | comment | added | David Z | FWIW it's not true that all three factors are supposed to be from the set of real numbers. They can be quantities with units. (Or potentially even vectors or some such thing that has the right properties to be an integration variable.) | |
Jul 5 at 15:13 | history | became hot network question | |||
Jul 5 at 8:53 | history | edited | DannyNiu | CC BY-SA 4.0 |
added 29 characters in body
|
Jul 5 at 8:42 | history | edited | Prem | CC BY-SA 4.0 |
added 11 characters in body; edited tags
|
Jul 5 at 8:37 | answer | added | Prem | timeline score: -1 | |
Jul 5 at 7:40 | history | edited | DannyNiu | CC BY-SA 4.0 |
deleted 3 characters in body
|
Jul 5 at 7:36 | vote | accept | DannyNiu | ||
Jul 5 at 7:34 | answer | added | Abezhiko | timeline score: 22 | |
Jul 5 at 7:11 | history | asked | DannyNiu | CC BY-SA 4.0 |